Normally, dividing by smaller and smaller numbers gives you bigger and bigger answers.

通常，随着除数的变小，得到的结果就会变大。

With some clever mechanical tricks, the Step Reckoner was also able to multiply and divide numbers.

利用一些机智的机械技巧 莱布尼茨乘法器也能够乘数和除数。

This question of counting the number of lattice points a distance sqrt(N) away from the origin involves adding up the value of this simple function over all divisors of N. Now, remember why we're doing all of this.

这个计算距原点 sqrt(N) 距离的格点数量的问题涉及将这个数的值与 N 的所有除数相加。 现在，请记住我们为什么要做这一切。